x^2*(2x-1)*(2x-1)=289

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Solution for x^2*(2x-1)*(2x-1)=289 equation: 


Simplifying
x2(2x + -1)(2x + -1) = 289

Reorder the terms:
x2(-1 + 2x)(2x + -1) = 289

Reorder the terms:
x2(-1 + 2x)(-1 + 2x) = 289

Multiply (-1 + 2x) * (-1 + 2x)
x2(-1(-1 + 2x) + 2x * (-1 + 2x)) = 289
x2((-1 * -1 + 2x * -1) + 2x * (-1 + 2x)) = 289
x2((1 + -2x) + 2x * (-1 + 2x)) = 289
x2(1 + -2x + (-1 * 2x + 2x * 2x)) = 289
x2(1 + -2x + (-2x + 4x2)) = 289

Combine like terms: -2x + -2x = -4x
x2(1 + -4x + 4x2) = 289
(1 * x2 + -4x * x2 + 4x2 * x2) = 289
(1x2 + -4x3 + 4x4) = 289

Solving
1x2 + -4x3 + 4x4 = 289

Solving for variable 'x'.

Reorder the terms:
-289 + 1x2 + -4x3 + 4x4 = 289 + -289

Combine like terms: 289 + -289 = 0
-289 + 1x2 + -4x3 + 4x4 = 0

The solution to this equation could not be determined.

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